Chemistry Ideal Gas Moles

Ideal-gas amount of substance. Distinct from moles-from-mass.

Moles = (P × V) ÷ (R × T) with R = 0.082057 L·atm/(mol·K).

Tip: Keep “Pressure (atm)” and “Volume (L)” on the same basis (period, units, and population) before calculating Chemistry Ideal Gas Moles.

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Ideal-gas moles equal PV divided by RT (R = 0.082057 L·atm·mol⁻¹·K⁻¹).

Enter P in atm, V in L, and T in kelvin.

Pressure in atmospheres
Volume in liters
Absolute temperature

Moles

Understanding Chemistry Ideal Gas Moles

How we calculate. Moles = (P × V) ÷ (R × T) with R = 0.082057 L·atm/(mol·K). The form uses the same arithmetic as the worked examples on this page. See our methodology and accuracy policy.

Real-world scenario: A typical Chemistry Ideal Gas Moles case uses pressure (atm) 1.00 and volume (l) 22.4. Enter the same figures below to reproduce the worked path.

What is Chemistry Ideal Gas Moles?

Ideal-gas amount of substance. Distinct from moles-from-mass.

  • P in atm
  • V in liters
  • T in kelvin

The Formula

Ideal Gas Law (n)
n = PV ÷ RT

Worked Example

Scenario: P = 1.00 atm; V = 22.4 L; T = 273 K.
Step 1: n = (1 × 22.4) ÷ (0.082057 × 273) ≈ 1.000
Answer: About 1.00 mol.

Common Use Cases

  • Homework: gas stoichiometry
  • Lab: collected-gas estimates
  • Study: STP drills

Pro Tips

  • Convert °C → K
  • Use atm and liters with this R
  • Ideal-gas assumption

Limitations: Chemistry Ideal Gas Moles results are educational chemistry study aids—not lab safety certification, clinical advice, or industrial process control. Use consistent units and confirm formulas with your textbook or instructor.

FAQ

Which R is used?

0.082057 L·atm·mol⁻¹·K⁻¹. Convert pressure/volume if you use another R.

What if T is 0 K?

n is undefined—enter positive absolute temperature.

Authoritative References

For chemistry study concepts, consult: